When p-1 and q-1 are both smooth numbers, n can be factorised using Pollard’s p-1 algorithm.

from gmpy2 import gcd, powmod, next_prime
from Crypto.Util.number import long_to_bytes

ct = 0x310a423b12a26d0c8244181d158571f973c42e9ebae9ae004aabd371568efaa199e4d163e6698ab3c372d80ceb97eb793ef5183eb931abe57fbdaae2fcf1e195ac16cdf1fe73fcecc35c931edee66f7a7a4c228a8f7edb1fa8902be03e95bf507e5a9ae43e87782da46655ff2a7efd192989e59348d4b520bd6d2485997d0b0f069449b231cd073c89ff792e18b7ca34a6cf6d18ffb7e43d2e0a5eb690f34fd8acb56dc986eb8bf524b311f331f25ecaea4f36cd71bda0f177bcfc27b121a871c126956928dca21528a57af8749b9bb92759dea2d054d434f3fe38178a20e3b1ed75d6afb60e83b15e9193594b4d5ad300bb40754c6886d79ccd0689353a2edd
n = 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
e = 65537

def pollard_pm1(N, g=2):
        k=2
        while True:
                g = powmod(g, k, N)
                p = gcd(g-1,N)
                if p != 1 and p != N:
                        return p, N//p
                k = next_prime(k)

p, q = pollard_pm1(n)
d = pow(e, -1, (p-1)*(q-1))
flag = long_to_bytes(pow(ct, d, n))
print(flag.decode())
#picoCTF{95d15b05}